Exploring Typescript: A Guide to Conditional Branching Based on Type

I encountered the following scenario:

interface C {
  c1: string;
  c2: number;
  c3: boolean;
}

interface D {
  d1: number;
  d2: boolean;
  d3: string;
}

function bar<K1 extends keyof C, K2 extends keyof D>(entry: K1 | K2) {
  if (entry includes key from interface C) { // <--- THIS IS WRONG!
    console.log('received type C');
  } else {
    console.log('received type D');
  }
}

bar('c1');
bar('d2');

What is the correct way to modify the if statement so that it correctly differentiates based on type?

I have attempted alternatives such as keyof, typeof, instanceof .... but none have been successful.

Answer №1

When it comes to interfaces, they are purely a compile-time concept and do not exist at runtime. This means that using a type in an expression poses a challenge since the type is not available during code execution.

To work around this limitation, we can create an object that includes all the keys of the interface - a collection that is guaranteed by the compiler to consist solely of those keys.

By leveraging this object in a custom type-guard, we can assist the compiler in narrowing down the type of the key being used.

An approach to achieve this would resemble the following:

interface A {
    a1: string;
    a2: number;
    a3?: boolean;
}

interface B {
    b1: number;
    b2: boolean;
    b3: string;
}

// Factory function for key type-guards
function interfaceKeys<T>(keys: Record<keyof T, 0>) {
    return function (o: PropertyKey): o is keyof T {
        return o in keys;
    }
}
// The objects here are compiler enforced to have all the keys and nothing but the keys of each interface
const isAkey = interfaceKeys<A>({ a1: 0, a2: 0, a3: 0 })
const isBkey = interfaceKeys<B>({ b1: 0, b2: 0, b3: 0 })


function foo<K1 extends keyof A, K2 extends keyof B>(input: K1 | K2) {
    if (isAkey(input)) { // custom type guard usage
        console.log('got A type');
        input // is K1
    } else {
        console.log('got B type');
        input // is K2
    }
}

foo('a1');
foo('b2');

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