Extending Record in Typescript: A Comprehensive Guide

When working on interfaces, I often find myself wanting to extend the type Record in order to define objects with predefined keys and optional values without knowing their names.

For instance:

interface Person extends Record<string, string>{
 phonenumber: number,
 name: string
}

However, I encountered an error:

Property 'phonenumber' of type 'number' is not assignable to 'string' index type 'string'

I'm unsure how to properly define my interface in a way that allows me to set phonenumber as a number type while leaving all other fields as string types.

Answer №1

After Titian Cernicova-Dragomir provided feedback on your original inquiry, it was noted that the subsequent typescript code will result in an error.

interface IPhone {
  phonenumber: number, // <= error
  [s:string]: string,
}

Is there a way to utilize a generic interface instead?, e.g.

interface IStringTMap<T> { [key: string]: T; }
interface IStringStringMap extends IStringTMap<string> { }
interface IStringNumberMap extends IStringTMap<number> { }

Alternatively, you could consider implementing the following interface, though it may not offer as much value since it compromises type safety and requires manual type checks for each property.

interface IPhone {
  phonenumber: number, // <= no more error
  [s: string]: string | number
}

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