Generating a unique serial ID using Angular/JS

Question

Generating a unique serial ID using Angular/JS

I am in the process of developing a function that will create a unique serial id by replacing a string with the format; xxxx-xxxx-xxxx-xxxx. The desired outcome is a serial like this: ABCD-1234-EFGH-5678, where the first and third parts consist of letters and the second and last parts are numbers. Below is my current code:

public generateUniqSerial() {
   return 'xxxx-xxxx-xxx-xxxx'.replace(/[x]/g, function (c) {
     let r = Math.random() * 16 | 0, v = c == 'x' ? r : (r & 0x3 | 0x8)
     return v.toString(16)
   })
 }

The above code gives a result similar to this: "7f8f-0d9a-fd5-450f". How can I modify this function to achieve the desired output in the format: ABCD-1234-EFGH-6789?

javascript angular typescript random uuid

Answer 1

Answer №1

If you're looking to create a unique Serial ID with a specific format like ABCD-1234-EFGH-5678, you can use the following function:

function generateRandomSerial() {
  let serial = '';
  const minChar = 10; // ASCII value for characters after '9'
  const maxChar = 62; // Total number of alphanumeric characters
  for (let i = 0; i++ < 4;) {
    let randomNum = Math.random() * (maxChar - minChar) + minChar << 0;
    serial += String.fromCharCode(randomNum += randomNum > 9 ? randomNum < 36 ? 55 : 61 : 48);
  }
  return serial;
}

function generateUniqueSerialID() {
  return `${generateRandomSerial()}-${generateRandomSerial()}-${generateRandomSerial()}-${generateRandomSerial()}`
}

console.log(generateUniqueSerialID())
console.log(generateUniqueSerialID())

Answer 2

If you're looking to create a unique Serial ID with a specific format like ABCD-1234-EFGH-5678, you can use the following function:

function generateRandomSerial() {
  let serial = '';
  const minChar = 10; // ASCII value for characters after '9'
  const maxChar = 62; // Total number of alphanumeric characters
  for (let i = 0; i++ < 4;) {
    let randomNum = Math.random() * (maxChar - minChar) + minChar << 0;
    serial += String.fromCharCode(randomNum += randomNum > 9 ? randomNum < 36 ? 55 : 61 : 48);
  }
  return serial;
}

function generateUniqueSerialID() {
  return `${generateRandomSerial()}-${generateRandomSerial()}-${generateRandomSerial()}-${generateRandomSerial()}`
}

console.log(generateUniqueSerialID())
console.log(generateUniqueSerialID())

Answer 3

Answer №2

When given tasks like this, my preferred method is to begin with a "series of letters" and a "series of numbers." From there, I simply pick a random location within the designated source string to retrieve each necessary character. This approach appeals to me as it is clear and straightforward, making it effortless to verify its functionality through desk-checking.

Answer 4

When given tasks like this, my preferred method is to begin with a "series of letters" and a "series of numbers." From there, I simply pick a random location within the designated source string to retrieve each necessary character. This approach appeals to me as it is clear and straightforward, making it effortless to verify its functionality through desk-checking.

Generating a unique serial ID using Angular/JS

Answer №1

Answer №2

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