Guide on how to navigate within an app by clicking on a link from an email

Question

Guide on how to navigate within an app by clicking on a link from an email

Is there a way to launch my Android application (Nativescript) from a link in an email that says "Click here to reset password"?

For example, the email contains a link like this:

When I click on this link from my mobile browser, I want the app to open to the resetPassword component.

I have tried the following code in my AndroidManifest.xml, but it only works for the URL :

        <intent-filter>
            <action android:name="android.intent.action.VIEW" />
            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <data android:scheme="http" android:host="secsystem.domain.tk" android:path="/v1/resetPassword"></data> 
        </intent-filter>

I have also added the route in routing.ts like this:

{ path: 'v1/resetPassword/:id', component: ResetPassIdComponent },

However, clicking on the link does not open the specified component. Is there any solution for this?

android angular typescript nativescript

Answer 1

Answer №1

In cases where the path contains dynamic parameters, it is recommended to utilize the android:pathPattern attribute.

For instance:

<intent-filter>
    <action android:name="android.intent.action.VIEW" />
    <category android:name="android.intent.category.DEFAULT" />
    <category android:name="android.intent.category.BROWSABLE" />
    <data android:scheme="http" android:host="example.domain.com" android:path="/v1/userProfile/.*"></data> 
 </intent-filter>

It is essential to specify this URL pattern so that Android knows to launch your app upon matching the specified criteria. Angular does not play a role in this scenario. To route to a specific component based on the URL pattern, manual handling is required.

To achieve this functionality, consider installing the custom plugin and extract the URL used to launch the app within the app component, triggering navigation in your router as needed.

import { Component, OnInit } from "@angular/core";
import { handleOpenURL, AppURL } from 'custom-plugin-name';

@Component({
  selector: "app-root",
  template: "<router-outlet></router-outlet>"
})
export class AppComponent {
    constructor() {
    } 

    ngOnInit(){
        handleOpenURL((appURL: AppURL) => {
            console.log('Received the following appURL', appURL);
        });
     }
}

Answer 2

In cases where the path contains dynamic parameters, it is recommended to utilize the android:pathPattern attribute.

For instance:

<intent-filter>
    <action android:name="android.intent.action.VIEW" />
    <category android:name="android.intent.category.DEFAULT" />
    <category android:name="android.intent.category.BROWSABLE" />
    <data android:scheme="http" android:host="example.domain.com" android:path="/v1/userProfile/.*"></data> 
 </intent-filter>

It is essential to specify this URL pattern so that Android knows to launch your app upon matching the specified criteria. Angular does not play a role in this scenario. To route to a specific component based on the URL pattern, manual handling is required.

To achieve this functionality, consider installing the custom plugin and extract the URL used to launch the app within the app component, triggering navigation in your router as needed.

import { Component, OnInit } from "@angular/core";
import { handleOpenURL, AppURL } from 'custom-plugin-name';

@Component({
  selector: "app-root",
  template: "<router-outlet></router-outlet>"
})
export class AppComponent {
    constructor() {
    } 

    ngOnInit(){
        handleOpenURL((appURL: AppURL) => {
            console.log('Received the following appURL', appURL);
        });
     }
}

Guide on how to navigate within an app by clicking on a link from an email

Answer №1

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