How can I include additional choices in a Query by utilizing typescript and sequelize?

Question

How can I include additional choices in a Query by utilizing typescript and sequelize?

Currently, I am in the process of developing a search and filter feature for a database. This feature will allow users to apply filters and search for specific entries. The technologies I'm using for this project are TypeScript and Sequelize.

My goal is to generate a list of items that match both the applied filters and the search term entered by the user. Here's how I envision my code working:

const { Op } = require('sequelize');
let options = {};

if(searchParameters.name){
    options += { [Op.like]: { itemName: '%' + searchParameters.name + '%'}}
}

return Item.findAll({
    where: options
}

I want the code to only implement filters that have been provided by the user and ignore any null filters. However, I'm currently facing challenges in making this functionality work as intended.

typescript search sequelize.js backend

Answer 1

Answer №1

Your goal is to create a JSON object with options including a where property. To achieve this, you can define the criteria for the options based on your preferences. The example provided has an incorrect format for the where arguments. You should aim for something similar to the following structure:

const options = {
  where: {
    itemName: {
      [Op.like]: `%${searchParameters.name}%',
    },
  },
};

To conditionally reach this result, you can follow a process like the one shown below:

const { Op } = require('sequelize');

// ... code

const where = {};

if (searchParameters.name){
  where.itemName = {
    [Op.like]: `%${searchParameters.name}%`,
  }
}

const items = await Item.findAll({ where });

Answer 2

Your goal is to create a JSON object with options including a where property. To achieve this, you can define the criteria for the options based on your preferences. The example provided has an incorrect format for the where arguments. You should aim for something similar to the following structure:

const options = {
  where: {
    itemName: {
      [Op.like]: `%${searchParameters.name}%',
    },
  },
};

To conditionally reach this result, you can follow a process like the one shown below:

const { Op } = require('sequelize');

// ... code

const where = {};

if (searchParameters.name){
  where.itemName = {
    [Op.like]: `%${searchParameters.name}%`,
  }
}

const items = await Item.findAll({ where });

How can I include additional choices in a Query by utilizing typescript and sequelize?

Answer №1

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