How can you sort an array in Typescript without considering letter case?

Question

How can you sort an array in Typescript without considering letter case?

I am attempting to alphabetize an array in TypeScript without regard to case sensitivity. In JavaScript, this could be achieved with

    list.sort(function (a, b) {
      return a.toLowerCase().localeCompare(b.toLowerCase());
    });

In TypeScript, the sorting logic resembles

    list.sort((a, b) => {
      if (a > b) {
        return 1;
      }
      if (a < b) {
        return -1;
      }
      return 0;
    });

Given [F, E, D, c, b, a] as input, I anticipate receiving [a, b, c, D, E, F]

The JavaScript sort method produces the anticipated outcome, but the TypeScript sort results in [D, E, F, a, b, c]. How can I enforce case insensitivity in the TypeScript sorting process?

EDIT: The reason I cannot employ the JavaScript technique is due to the fact that in TypeScript, variables a and b are of boolean type and do not possess the toLowerCase() method.

arrays sorting typescript

Answer 1

Answer №1

Here is a different approach to sorting the array that may be more concise and cleaner. The function `sortStrings` provided here converts the elements to lowercase before comparing them, ensuring case-insensitive sorting. This function works effectively for strings of any type as well.

function sortStrings(a: string, b: string) {
    a = a.toLowerCase();
    b = b.toLowerCase();
    return a > b ? 1 : (a < b ? -1 : 0);
}

console.log(['F', 'E', 'D', 'c', 'b', 'a'].sort(sortStrings));

Output:

[ 'a', 'b', 'c', 'D', 'E', 'F' ]

Answer 2

Here is a different approach to sorting the array that may be more concise and cleaner. The function `sortStrings` provided here converts the elements to lowercase before comparing them, ensuring case-insensitive sorting. This function works effectively for strings of any type as well.

function sortStrings(a: string, b: string) {
    a = a.toLowerCase();
    b = b.toLowerCase();
    return a > b ? 1 : (a < b ? -1 : 0);
}

console.log(['F', 'E', 'D', 'c', 'b', 'a'].sort(sortStrings));

Output:

[ 'a', 'b', 'c', 'D', 'E', 'F' ]

How can you sort an array in Typescript without considering letter case?

Answer №1

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