How is it possible to utilize type assertions with literals like `false`?

When working in TypeScript, I came across an interesting observation when compiling the following code:

const x = true as false;

Surprisingly, this direct assertion is valid, creating a constant x with the value true and type false. This differs from the expected behavior of such assertions being invalid. For example, attempting similar code:

const x = 0 as false;

results in a compilation error.

The conversion of type 'number' to type 'false' raises a warning due to insufficient overlap between the types. To proceed intentionally, it's recommended to convert the expression to 'unknown' first.

Given this outcome, I was left wondering why no error occurs with true and false - and whether there might be specific compiler options or settings that could address this inconsistency.

Answer №1

The reason behind this occurrence is that typescript extends the definition of the types themselves. Although true and false fall under the boolean type category, they do have some overlapping characteristics. On the other hand, 0 and false do not overlap as one belongs to the number type while the other falls under the boolean type.

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