How to simulate keyboard events when a dropdown list is opened in an Angular application

Requirement-

A situation arises where upon opening the dropdown menu, pressing the delete key on the keyboard should reset the index to -1.

Steps to reproduce the issue: 1. Click on the dropdown and select an option from the menu. 2. Click on the dropdown again to open the menu, then press the delete key on the keyboard. 3. Currently, the keydown/up event does not get triggered when the delete key is pressed.

Expectation- The keydown event should be triggered when the delete key is pressed while the dropdown menu is open.

I would appreciate any suggestions on how to trigger the keyboard event when the dropdown is open.

Access stackblitz

Answer №1

This solution offers a straightforward approach to the issue, with the select element bound to an ngModel. The keyup event is utilized to detect delete or backspace input, reverting to the default value if necessary.

html

<select #myDropdown [(ngModel)]="selectedValue" (keyup)="onKeyUp($event)">
 <option value="0">Select Option</option>
 <option value="1">Option 1</option>
 <option value="2">Option 2</option>
 <option value="3">Option 3</option>
</select>

In the TypeScript file:

export class AppComponent {
name = 'Angular ' + VERSION.major;
selectedValue = 0;

constructor(private elementRef: ElementRef) {}

ngAfterViewInit() {
const dropdownElement =
this.elementRef.nativeElement.querySelector('#myDropdown');
}

onKeyUp(event: KeyboardEvent) {
if (event.key === 'Delete' || event.key === 'Backspace') {
// Your deletion logic here
// For example, select the next item in the list:
this.selectedValue = 0;
}
}
}

I hope this explanation proves helpful :)

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