I am currently working to resolve this particular wildcard issue with the help of TypeScript

I've been working on solving the wildcard problem with TypeScript, but I'm running into issues with some of the test cases I've created. Here's a brief overview of how the code operates:

A balanced string is one where each character appears the same number of times as every other character

Examples of balanced strings include "ab", "aaabbb", and "ababaabb", while "abb" and "abbaa" are not balanced.

function balanced(s: string): boolean {
  const MAX = 1000;
  let wildcards: number = 0;
  const map: { [key: string]: number } = {};
  let characterCount = 0;
  
  // Code implementation omitted for brevity
  
}

I am evaluating the code with the following test inputs:

1: "a" should return true
2: "ab" should return true
3: "abc" should return true
4: "abcb" should return false
5: "Aaa" should return false
6: "abcb*" should return false
7: "abcb**" should return true
8: "***********" should return true
9: "" should return true
10: "abd*xdx*yba*" should return true
11: "aabb***" should return false
12: "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ" should return false
13: "JB**JTIT*****EY" should return false

Answer №1

Test case 12: When given the input "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ", the function should return false

No, according to the test results, it should actually return true. All other test cases are passing successfully.

https://example.com/test-case-12

Answer №2

I encountered a similar issue and managed to solve it by tweaking the solution slightly.

const factorPairs = (n: number) =>
  [...Array(Math.floor(Math.sqrt(n)))].map((_, i) => i + 1)
    .flatMap(f => n % f == 0 ? [[f, n / f], [n / f, f]] : []);

const balanced = (s: string): boolean => {
  if (!s) return true;
  const ss = s.split('');
  const chars = [...new Set(ss.filter(s => s !== '*'))];
  const counts = ss.reduce(
    (counts, s) => s === '*' ? counts : ((counts[s] += 1), counts),
    Object.fromEntries(chars.map(l => [l, 0]))
  );
  const maxCount = Math.max(...Object.values(counts));
  return factorPairs(ss.length).some(
    ([count, letters]) =>
      letters <= 52 &&
      letters >= chars.length &&
      count >= maxCount
  );
};

link to original solution

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