I am struggling to understand how to work with constrained generic functions

function calculateMinimumLength<T extends {length : number}>(arg1: T, arg2: T) : T {
    if (arg1.length >= arg2.length) {
        return arg2;
    } else {
        return arg1;
    }
}

let str = "Hello world"; 
const result0 = calculateMinimumLength([1, 2, 3], str); // Argument of type 'number[]' is not assignable to parameter of type 'string'
const result1 = calculateMinimumLength([1, 2, 3], {length: 12}); // result1 type - number[] | {length: number}

In the provided code snippet, calling calculateMinimumLength([1, 2, 3], {length: 12}) functions correctly while calculateMinimumLength([1, 2, 3], str) results in a type error.

It seems like there should not be a type error in the second call and result0 should be assigned a type of: number[] | string. However, TypeScript does not infer this for result0 but it does for result1. This difference in behavior might be due to how TypeScript handles different data types in function generics.

Answer №1

Generics in Typescript serve to limit the type of parameters and deduce the type of arguments provided.

Imagine a scenario where a user inputs the generic value manually:

getMinimum<number[]>([1, 2, 3], str)
. It becomes evident that number[] aligns with [1, 2, 3] but not with "Hello world".

It is essential to have a distinct generic for each parameter when their types differ, even if they meet the same criteria:

type Length = { length : number };

function getMinimum<T extends Length, U extends Length>(arg1 : T, arg2 : U) : T | U {
    if (arg1.length >= arg2.length) {
        return arg2;
    }

    else {
        return arg1;
    }
}

The reason why

getMinimum([1, 2, 3], { length: 12 })
succeeds with your implementation while getMinimum([1, 2, 3], str) does not can be explained as follows:

Please note: This explanation is based on personal understanding.

When associating two arguments with a single generic, TS likely undergoes the following process:

  • Deduce the types of each argument individually;
  • Verify if these types satisfy the constraint;
  • If they do not, reject the arguments;
  • If they do, intersect them to identify a common type;
  • If the intersection results in never, discard the first argument and highlight the second in the error message.

In the case of

getMinimum([1, 2, 3], { length: 12 })
: TS infers number[] for arg1 and {length: number} for arg2, checks their compatibility with { length: number }, then combines them, resulting in number[] and accepts the type.

With getMinimum([1, 2, 3], str): TS deduces number[] for arg1 and string for arg2, verifies their fit with { length: number }, intersects them, leading to never and declining the first argument.

A unified type that satisfies both { length: number } for number[] and string would be

{ length: number } & (string | number[])
, yet TS does not attempt to infer this type. This could be due to the intention of determining the most specific type possible rather than broadening it, as narrower types are more beneficial.

It is crucial to differentiate between type inference and type validation: TS can accurately infer the return type even if the type checker disapproves of the arguments, as these are separate processes. In this context, it is evident that T should be typeof arg1 | typeof arg2 in the return type position.

Answer №2

The cause of your error can be traced back to the implicitly inferred types of the arguments being passed. To address this issue and ensure that your function can accept both an array and a string, you can utilize a union type:

function determineMinimum<T extends { length: number }>(input1: T, input2: T | string): T {
  if (input1.length >= (input2 as T).length) {
    return input2 as T;
  } else {
    return input1;
  }
}

Another approach would be to specify the generic type explicitly in the variable result:

const result = determineMinimum<number[] | string>([4, 5, 6], str);

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