In TypeScript, the constructor parameter is automatically inferred as type "any"

Let's dissect the code snippet provided below:

class Person {
    private name: string;
    constructor(name){
        this.name = name;
    }
}

let p = new Person(5)

The above code does not result in any errors. One would expect an error to occur during the constructor call, where the value 5 is passed.

It appears that the name parameter in the constructor is being inferred as any, even though it is clear that we are assigning it to private name: string.

So the question remains: is there a specific reason why TypeScript allows the value 5 here - or put differently - why is name being inferred as any, when it should clearly be a string in this context?

I am aware that I could define another class structure like this:

class Person {
    constructor(
        private name: string
    ){}
}

In this case, the parameter type is explicitly specified, eliminating any inference. Similarly, I could also write:

class Person {
    private name: string;
    constructor(name: string){
        this.name = name;
    }
}

and avoid any inference as well. However, my focus here is on understanding the mechanism of inference and why it operates in this manner.

Answer №1

To handle this issue, there is a specific compiler option known as noImplicitAny. When you set "noImplicitAny": true, the type of your name will not be automatically inferred as any, preventing it from accepting any type without complaint.

Have you ever wondered why it functions in this manner?

For more information, refer to this link and this one.

Answer №2

When declaring a contructor with just the parameter name, it is essentially equivalent to declaring it as constructor( name: any ). This allows for seamless assignment of this.name = name only because TypeScript (TS) maintains backward compatibility with vanilla JavaScript. TS assumes that you are aware of the types being passed, hence enabling assignments with 'any' values. Consequently, control and responsibility for conversions between number and string are left outside of TS's domain.

Answer №3

It seems to me that the issue at hand involves both ambiguity and the complexity of computations.

To start with, having simple rules that cover a majority of cases tends to be the most efficient approach. This simplicity in the language's grammar makes it easier for newcomers to learn and for the compiler to maintain itself.

In certain scenarios, determining the type of an argument through its usage may lead to extensive traversal, potentially slowing down compilation if there are errors in the code.

The constructor serves as a type's external interface, interacting with other parts of the application. For clarity and safety, this interface should be explicit. Relying on the actual implementation implicitly can result in unintentional changes during refactoring, leading to hard-to-detect bugs.

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