Incorporating numerous query parameters in Angular version 14

Question

Incorporating numerous query parameters in Angular version 14

I am currently working on developing a multi-item filter feature for my application and I am faced with the challenge of sending multiple query parameters in the API request to retrieve filtered items.

My main concern is whether there is a more efficient way to handle this task rather than manually adding all the query parameters, given that there are around 40-50 filtering options. Is there a way to programmatically generate these query parameters?

I believe creating an object manually would suffice, but I am curious if there exists a simpler method to achieve this.

angular typescript angular14

Answer 1

Answer №1

A feasible option is to automatically generate query parameters through programming.

One approach is to keep an array of parameter key/value pairs by utilizing Object.entries to convert an object into an array of key/value pairs, and using Object.fromEntries to reverse the process.

const params = { currency: 'USD', language: 'en-US' }
// converting to [['currency', 'USD], ['language', 'en-US']]
const arrayOfParams = Object.entries(params) 
// converting back to { currency: 'USD', language: 'en-US' }
const paramsObj = Object.fromEntries(arrayOfParams)

Then make use of HttpParams to transform an object into query parameters:

import { HttpParams } from '@angular/common/http'
const paramsObj = { currency: 'USD', language: 'en-US'}
const params = new HttpParams({ fromObject: paramsObj })

/* Serializes the body to an encoded string, 
*  where key-value pairs (separated by =) are separated by &s. 
*/
const queryStr = params.toString()

Answer 2

A feasible option is to automatically generate query parameters through programming.

One approach is to keep an array of parameter key/value pairs by utilizing Object.entries to convert an object into an array of key/value pairs, and using Object.fromEntries to reverse the process.

const params = { currency: 'USD', language: 'en-US' }
// converting to [['currency', 'USD], ['language', 'en-US']]
const arrayOfParams = Object.entries(params) 
// converting back to { currency: 'USD', language: 'en-US' }
const paramsObj = Object.fromEntries(arrayOfParams)

Then make use of HttpParams to transform an object into query parameters:

import { HttpParams } from '@angular/common/http'
const paramsObj = { currency: 'USD', language: 'en-US'}
const params = new HttpParams({ fromObject: paramsObj })

/* Serializes the body to an encoded string, 
*  where key-value pairs (separated by =) are separated by &s. 
*/
const queryStr = params.toString()

Answer 3

Answer №2

To effectively manage the filter options, consider creating an object dedicated to this task.

Once you have all the filter options stored in the object, you can easily convert it to JSON using the JSON.stringify method.

If you wish to exclude any null or undefined values from the final JSON output, you can utilize a replacer function.

let opt = {
    a: 'string',
    b: 5.1,
    c: true,
    d: { e: 'object' },
    f: ['array'],
    g: null,
    h: undefined,
  };
  
console.log(JSON.stringify(opt, (key, value) => {
    if (value !== null) return value;
}));

Answer 4

To effectively manage the filter options, consider creating an object dedicated to this task.

Once you have all the filter options stored in the object, you can easily convert it to JSON using the JSON.stringify method.

If you wish to exclude any null or undefined values from the final JSON output, you can utilize a replacer function.

let opt = {
    a: 'string',
    b: 5.1,
    c: true,
    d: { e: 'object' },
    f: ['array'],
    g: null,
    h: undefined,
  };
  
console.log(JSON.stringify(opt, (key, value) => {
    if (value !== null) return value;
}));

Incorporating numerous query parameters in Angular version 14

Answer №1

Answer №2

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