Interface displaying auto-detected car types

I have a setup that looks like this:

interface ValueAccessor<T> {
    property: keyof T;
    getPropertyValue: (value: any) => value;
}

I am trying to figure out how to define the correct type and replace the any when I want to provide a custom getPropertyValue function to retrieve a specific property of T.

The desired interface I'm looking for is:

interface User {
    username: string;
    email: string;
}

const valueAccessor: ValueAccessor<User> = {
    property: 'username',
    getPropertyValueFunction: … 
    // The goal here is for the type checker to identify that
    // the proper type of this function should be: (value: string) => string, as
    // the property selected is 'username' and the type of User['username'] is string.
}

If I wish to access another property like email:

const valueAccessor: ValueAccessor<User> = {
    property: 'email',
    getPropertyValueFunction: … Expected type: (value: string) => string
}

Answer №1

To resolve this issue, consider specifying the desired property key as a type argument within your ValueGetter interface.

For example:

interface ValueGetter<T, K extends keyof T> {
    propertyKey: K;
    valueFunction: (value: T[K]) => T[K];
}

const myValueGetter: ValueGetter<User, 'name'> = {
    propertyKey: 'name', // only 'name' is allowed here
    valueFunction: … Expected function type: (value: string) => string
}

Answer №2

interface DataRetriever<U,V extends keyof U> {
    dataKey: V,
    retrieveData: () => U[V];
}

interface User {
    id: number;
    username: string;
}

const user : User = {
    id: 12345,
    username: "JaneDoe"
}

const idRetriever  : DataRetriever<User, 'id'> = {
    dataKey: 'id',
    retrieveData: () => user[idRetriever.dataKey]
} 


This implementation serves the purpose you described. The redundancy in property declaration is present but functional. Without using V, TypeScript would default to displaying all property types (such as number | string here)

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