Is it feasible to restrict generic classes for particular functions?

Imagine creating a customized container in TypeScript. Let's consider this straightforward example:

class Container<T> {
  val: T;
  constructor(t: T) {
    this.val = t;
  }
}

Now, let's say you want to implement a function that can generate a new container by adding the values of two containers with numeric data.

class Container<T> {
  val: T;
  constructor(t: T) {
    this.val = t;
  }
  add(c: Container<number>): Container<number> {
    return new Container(this.val + c.val);
  }
}

However, there's a challenge in getting the above code to pass the typecheck parameter. Since the type of this.val is undefined, it becomes complex to constrain the add method for instances where T == number. Is there a solution using TypeScript?

The example mentioned above is just simplification. The ultimate goal is to establish a TypeScript interface for applicative functors. Essentially, an applicative functor includes a method that could be defined for Container similar to this:

ap<A, B>(c: Container<A>): Container<B> {
  return new Container(this.val(c.val));
}

This would require ensuring that T == (a: A) => B. On a broader scale, the intention is to define an interface like this:

interface Applicative<T> {
  ...
  ap: <A, B>(a: Applicative<A>) => Applicative<B> // where T == (a: A) => B
  ...
}

Does TypeScript provide a solution for these scenarios?

Answer №1

Restrictions for the variable T cannot be limited to a single method; they must be applied at the class level.

Answer №2

Constraints can be applied to generic types for added specificity.

An example of this in action could look like the following:

interface ContainsNumber {
    numValue: number;
}

class Box<T extends ContainsNumber> {
}

It's worth noting that constraints cannot be set using primitive data types like number, string, or boolean.

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