Is it possible to use this type in TypeScript?
type Person = {
who: string;
}
type Person = Person.who === "me" ? Person & Me : Person;
Is it possible to use this type in TypeScript?
type Person = {
who: string;
}
type Person = Person.who === "me" ? Person & Me : Person;
I believe utilizing a discriminated union might be the solution:
type Myself = {
identity: 'myself',
secret: string;
}
type Another = {
identity: 'another',
}
type Individual = Myself | Another;
Absolutely, you have the capability to achieve this using Generics, Distributive Conditional Types and Unions.
Here is a simple example to demonstrate how it can be done:
type Somebody<T extends string> = {
who: T;
}
type Myself = {
me: boolean;
}
type Thatother<T extends string> = T extends 'me' ? Somebody<T> & Myself : Somebody<T>;
function identify<T extends string>(who: T) {
return {
who,
me: who === 'me' ? true : undefined
} as Thatother<T>
}
const x = identify('someone');
const y = identify('me');
x.who; // works fine
x.me; // shows error
y.who; // works fine
y.me; // also fine
Check out the TypeScript playground for a live demonstration here.
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