Is it possible to declare an object literal with optional keys in a Typescript function signature?

I have a .d.ts file similar to this:

declare function myfunc(): {
  something: (err, { req, res, errorInfo, query, pathname, extra }?) => void;
};

This declaration states that the function takes two arguments, with the second argument being an optional "options" object.

However, I am looking for a way to also make the keys of the options object optional, allowing me to pass a partial object as the second argument.

Can someone provide guidance on the correct syntax for achieving this?

Answer №1

It is important to provide a name for the second argument as well. This way, you can designate it as optional.

function myfunc(): {
  doSomething: (error: any, newArg?: { request: any, response: any }) => void;
};

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