Is it possible to denote two "any" as the same thing in a TypeScript function signature?

Here is a function to extract items from an array based on a checker function:

function extractItemsFromArray(array: any[], isItemToBeRemoved: (item: any) => boolean) {
  let removedItems = [];
  let i = array.length;
  while(i--)
    if(isItemToBeRemoved(array[i]))
      removedItems.push(array.splice(i, 1));
  return removedItems;
}

The function accepts an array of any items and a checker function that determines whether to remove an item. However, there is a potential issue if a function with the signature (item: string) => boolean is passed as isItemToBeRemoved, and a number[] is passed as array. The function definition does not specify that these two any types should be the same. Is there a way to ensure that both instances of any are the same type in the function definition?

Answer №1

After doing some research while formulating the question, I decided to delve deeper into the topic of Advanced Types. It turns out that type aliases are exactly what I need:

function extractItemsFromArray<T>(array: T[], isItemToBeRemoved: (item: T) => boolean) {
  ...
}

Here's how you can use it:

let roots = extractItemsFromArray<INode>(dictionaryCopy, item => !item.parentId);

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