After analyzing this segment of code, I noticed an interesting expression:
!args.value || args.value.length
For instance, consider the following scenario:
let v = {};
console.log(!v.value); //outputs true
console.log(v.value); //outputs undefined
console.log(v.value.length); //Script error - cannot read property length of undefined
Despite the value being undefined, the validation proceeds to check if args.value.length (or undefined) is less than a constraint. Effectively, it may resemble something like this (if I understand correctly):
true throws
!undefined || undefined.length < 4
Initially, I thought the purpose of the first condition was to ensure that the variable undefined
is actually defined?
So, shouldn't it be
args.value && args.value.length
? Simply put:
If args.value exists, then verify its length?
To provide more clarity, here's the complete snippet within context:
if (isMinLength && (!args.value || args.value.length < args.constraints[0])) {
return eachPrefix + "$property must be longer than or equal to $constraint1 characters";