Is there a way to expand the return type of a parent class's methods using an object

Question

Is there a way to expand the return type of a parent class's methods using an object

Currently, I am enhancing a class by adding a serialize method. My goal is for this new method to perform the same functionality as its parent class but with some additional keys added.

export declare class Parent {
    serialize(): {
        x: number;
        y: number;
    };
}

export default class Child extends Parent {
    serialize() {
        return {
            ...super.serialize(),
            something: 'extra'
        };      
    }
}

I am interested in defining a type specifically for my extended class - perhaps named SerializedChild. Is it feasible in this scenario, and if so, what steps should I take to achieve that?

typescript

Answer 1

Answer №1

Here is the final outcome

interface CustomizedChild {
    // Include properties from Parent.serialize
    xPosition: number;
    yPosition: number;
    // Add any additional features
    specialTrait: string;
}

class UpdatedChild extends Parent {
    serialize(): CustomizedChild {
        return {
            ...super.serialize(),
            specialTrait: 'bonus'
        };
    }

    // Additional methods...
}

Answer 2

Here is the final outcome

interface CustomizedChild {
    // Include properties from Parent.serialize
    xPosition: number;
    yPosition: number;
    // Add any additional features
    specialTrait: string;
}

class UpdatedChild extends Parent {
    serialize(): CustomizedChild {
        return {
            ...super.serialize(),
            specialTrait: 'bonus'
        };
    }

    // Additional methods...
}

Is there a way to expand the return type of a parent class's methods using an object

Answer №1

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