Is there a workaround in TypeScript to add extra details to a route?

Typically, I include some settings in my route. For instance:

              .when('Products', {
                templateUrl: 'App/Products.html',
                settings: {
                    showbuy: true,
                    showexport: true,
                    Description: "Product List"
                },[...]

However, since working with TypeScript and angularJS, I've encountered limitations with the IRouteProvider interface in saving custom settings objects. The IRoute interface lacks properties for storing such custom settings.

Currently, I am only able to set the predefined properties of the IRoute interface as follows:

app.config([
            <any>'$routeProvider', function routes($routeProvider: ng.route.IRouteProvider) { $routeProvider
                    .when('/Product',
                    {
                         templateUrl: 'App/Products.html',
                         controller:'someController'
                         [...]
                    })

The angular js ng-route interface is defined as:

interface IRouteProvider extends IServiceProvider {     
    otherwise(params: IRoute): IRouteProvider;
    when(path: string, route: IRoute): IRouteProvider;
}
/**
 * see http://docs.angularjs.org/api/ngRoute/provider/$routeProvider#when    for API documentation
 */
interface IRoute {
    /**
     * {(string|function()=}
     * Controller fn that should be associated with newly created scope or the name of a registered controller if passed as a string.
     */
    controller?: string|Function;
    /**
     * A controller alias name. If present the controller will be published to scope under the controllerAs name.
     */
    controllerAs?: string;
    /**
     * Undocumented?
     */
    name?: string;
    [...]

This led me to wonder if there might be a workaround to store a custom object for each defined route.

Answer №1

To implement a new functionality, one can create a custom interface that extends the existing ng.route.IRoute interface. By casting the route definition as the newly defined interface, the desired features can be incorporated seamlessly.

First, establish the new interface:

export interface IExtendedRoute extends ng.route.IRoute {
    additionalProperty: string;
}

Next, utilize the newly created interface for route casting:

angular.module('App').config(['$routeProvider',
    function setupRoutes($routeProvider: ng.route.IRouteProvider) {
        $routeProvider
            .when('/', <IExtendedRoute> {
                controller: App.Controllers.HomeController,
                controllerAs: 'vm',
                templateUrl: './views/app/home.html',
                additionalProperty: 'SomeValue'
            })
            .otherwise('/');
    }
]);

Integrate the new property in relevant sections such as $routeChangeSuccess event:

angular.module('App').run(['$rootScope', '$location',
    function handleEvents($rootScope: ng.IRootScopeService, $location: ng.ILocationService) {
        $rootScope.$on('$routeChangeSuccess',
            function processChange(event: ng.IAngularEvent, current: IExtendedRoute, previous: ng.route.IRoute) {
                $rootScope['additionalProperty'] = current.additionalProperty;
            }
        );
    }
]);

A helpful resource on interface casting and its implications can be found in this insightful answer. It explains the compile-time nature of TypeScript interfaces and provides in-depth details from the TypeScript specification.

Answer №2

It is possible to include any additional properties in an object literal without affecting its compatibility with the interface. For instance, the code snippet below will compile successfully:

interface I {}

var i: I = { a: 1 };

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