Issues arise when attempting to use recursive types in combination with optional properties

In my code, I've created a type definition that allows me to traverse an object using an array of strings or indices representing the keys of the object or nested arrays:

export type PredicateFunction<ArrayType> = (array: ArrayType, index?: number) => boolean;
export type IndexOrPredicateFunction<Type> = number | PredicateFunction<Type>;
export type StatePathKey = IndexOrPredicateFunction<any> | string;

export type StatePath<Obj, Path extends (string | IndexOrPredicateFunction<any>)[] = []> =
    object extends Obj
        ? Path
        : Obj extends object
            ? (Path |
                    // Check if object is array
                    (Obj extends readonly any[] ?
                        // ...when array only allow index or PredicateFunction
                        StatePath<Obj[number], [...Path, IndexOrPredicateFunction<Obj[number]>]>
                        // ...when object generate type of all possible keys
                        : { [Key in string & keyof Obj]: StatePath<Object[Key], [...Path, Key]> }[string & keyof Obj]))
            : Path;

This setup works well with an interface like this:

interface State1  {
    test: {
        nestedTest: boolean
    }
}

where we can use it like this:

const t1: StatePath<State1> = ['test', 'nestedTest']; 

However, it encounters issues when dealing with optional properties like in this interface:

interface State2  {
    test: {
        nestedTest?: boolean
    }
}

I'm struggling to find a solution for this. I've tried using -? on the type without success. Any suggestions on how to overcome this challenge? You can try reproducing the issue in this TypeScript playground here.

Answer №1

To address this specific issue, a straightforward solution would be to update your check from object extends Obj to

object extends Required<Obj>
. In cases where Obj is considered as a weak type, implying that it's an object type with all properties being optional, TypeScript will view the empty object type {} and the object type as assignable to it. For instance,
object extends {a?: string, b?: number}
returns true. However, this approach can lead to unexpected behavior.

There are several strategies to tackle this, but by employing the Required<T> utility type, you compare object against a modified version of the type where the optional properties are transformed into required ones. Thus, while

object extends {a?: string, b?: number}
evaluates to true,
object extends Required<{a?: string, b?: number}>
(or
object extends {a: string, b: number}
) returns false. Consequently, the type won't bail out unless Obj truly lacks necessary specifications or is solely object, unknown, etc.

Playground link for code experimentation

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