I've added a check, so why is TypeScript still complaining about the possibility of my property being undefined?

const handleLinkClick = (index: number) => () => {
  const hasUrl = !!searchItems[index]?.url;
  if (hasUrl) {
    navigateToLink(searchItems[index]?.url);
  } else {
    setItemSelected(index);
  }
};

However, the issue I encountered is:

(property) url?: string | undefined
Argument of type 'string | undefined' is not assignable to parameter of type 'Url'.
  Type 'undefined' is not assignable to type 'Url'.

Answer №1

Due to TypeScript's inability to deduce from the utilization of the hasUrl variable back to the presence of the property, it is advisable to use the following approach:

const handleClick = (index: number) => () => {
  const url = searchTypes[index]?.url
  if (url) {
    router.push(url);
  } else {
    setSelectedSearchType(index);
  }
};

1: This does not imply that it cannot be done theoretically, it simply means that the implementation in the compiler is lacking. The usage of !! further complicates matters.

Answer №2

Another trick is to add an exclamation mark ! at the end of a variable declaration to ensure the type is not undefined.

const link = searchOptions[key]?.link!

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