Mastering the art of typing a member of an abstract generic class in Typescript with consideration for potential additional implementations

It's quite challenging to put into words, but essentially I aim to create a base abstract class outlining an abstract interface that must vary based on whether a derived class implements a specific interface or not.

Here is a TypeScript playground demonstrating the issue - everything seems to be functioning well and the types are correct externally from the class, yet TypeScript is flagging type errors internally.

playground

Answer №1

Utilizing Polymorphic this may not fully solve your problem here; unlike Java, there's no explicit way in TypeScript to declare a class as final. This means that the polymorphic this might have to refer to a more precise type within an unknown subclass context. For instance:

class Foo extends Derived {
  map(val: number) {
    return "oops";
  }
}
new Foo(7).getDefaultVal().toUpperCase(); // error at runtime

In this scenario, even after extending Derived with no compile-time issues, calling Foo.getDefaultVal() relies on inheriting from Derived, where the expected return type is supposed to be DeriveMapVal<this, number>, and in this case, this should resolve to Foo. As a result, DeriveMapVal<Foo, number> points to a string, while Foo's implementation just returns a number, leading to a compiler error due to the inability to verify if number is assignable to DeriveMapVal<this, number>.


To address this issue, one possible solution involves refining the subclass implementation to explicitly reference the self-class rather than relying on this:

class Derived extends Generic<number> {
  getDefaultVal(): DeriveMapVal<Derived, number> {
    return 0; // valid
  }
}

This approach may provide a resolution, despite the fact that you can still extend

Derived</code as usual, and the compiler correctly identifies that <code>Foo
is not compatible with Derived:

class Foo extends Derived {
  map(val: number) {
    return "oops";
  }
}

new Foo(7).getDefaultVal().toUpperCase(); // now also produces a compile-time error
const d: Derived = new Foo(10); // error
const g: Generic<number> = new Foo(20); // error

The declaration class Foo extends Derived does not necessarily ensure that Foo extends Derived is true. It's quite peculiar behavior. If you are able to handle this limitation, approaching it in such a manner could offer a path forward.

Hopefully, this provides some insights and assistance for your situation. Best of luck!

Click here to view the code in Playground

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