Navigating Nonexistent Object Properties in Typescript

How can I handle non-existing object properties in TypeScript?

In the scenario below, TypeScript raises an error for fooBar[foo] -

Element implicitly has an 'any' type because expression of type '"fooBar"' cannot be used to index type '{ readonly foo: "bar"; readonly bar: "foo"; }'.
  Property 'fooBar' does not exist on type '{ readonly foo: "bar"; readonly bar: "foo"; }'

What is the most appropriate way in TypeScript to address this issue?

const fooBar = {
    foo: 'bar',
    bar: 'foo'
} as const

const foo: 'foo' | 'fooBar' = 'fooBar';

const op: 'foo' | "bar" | 'default' = fooBar[foo] || 'default';

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Answer №1

When dealing with the value of foo, it can only be either "foo" or "fooBar". This causes an issue when using fooBar[foo] because "fooBar" is not a valid key in keyof typeof fooBar.

To workaround this and silence the compiler, you have to deceive it by doing the following:

type FooBar = typeof fooBar
const op: FooBar[keyof FooBar] | 'default' =
    fooBar[foo as keyof FooBar] || 'default';

In reality, this solution involves lying to the compiler because you are aware that foo can only be "foo" or "fooBar", making "fooBar" an invalid key in fooBar.

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