TypeScript's type inference feature functions well in scenario one but encounters an error in a different situation

I recently tried out TypeScript's type inference feature, where we don't specify variable types like number, string, or boolean and let TypeScript figure it out during initialization or assignment.

However, I encountered some confusion in its behavior.

For example, in Case 1:

function func(arg1:number, arg2:string){
console.log(arg1 + arg2);
}

let v ;
v = func;
console.log(typeof v);
v = 8;
console.log(typeof v);

The code runs without errors, resulting in output: function and number

But in Case 2:

function func(arg1:number, arg2:string){
console.log(arg1 + arg2);

}

let v = func;
console.log(typeof v);
v = 8;
console.log(typeof v);

In this case, the TypeScript compiler throws an error: Type 'number' is not assignable to type '(arg1: number, arg2: string) => void'.

Can anyone help me figure out what I'm missing? ~

Answer №1

From my perspective, the difference lies in how v is initially declared and inferred in the code. In the first scenario, v is declared without a specific type, allowing for multiple changes to its type throughout the code. However, in the second scenario, v is explicitly declared as a function from the start. TypeScript will then enforce this declaration, preventing any subsequent type changes that deviate from it.

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