Organize nested tuples and maintain their sequence

I am attempting to achieve a functionality similar to the following:

type Type = object;
type TypeTuple = readonly Type[];

function flattenTuples<T extends readonly (Type | TypeTuple)[], R = Flatten<T>>(...tuples: T): R {
  // code to flatten tuples and maintain correct order
  // example: flattenTuples(A, B, [C, D], [A]) => [A, B, C, D, A]
}

In this scenario, the flattenTuples function will flatten each tuple provided as a parameter and the implementation of type Flatten<T> will return a tuple in the form of a "as const" array while keeping the original ordering of the parameter tuple. It is important to note that only one level of flattening is required.

For instance, using different class constructors (A, B etc):

const flat = flattenTuples(A, B, [C, D], [A]);
// this line would define the variable flat with the type:
// [A, B, C, D, A]

I have explored a solution from a similar question, but the proposed Flatten type did not yield the desired outcome. With the given example, it resulted in the type [A, B, C | D, A]

Answer №1

UPDATE for TypeScript 4.5:

With the introduction of recursive conditional types and tail recursion elimination, defining a type like Flatten<T> to flatten arbitrary arrays becomes more straightforward.

type Flatten<T extends readonly any[], A extends readonly any[] = []> =
    T extends [infer F, ...infer R] ?
    Flatten<R, F extends readonly any[] ? [...A, ...F] : [...A, F]> :
    A

type InputTuple = [A, B, [C, D], [A, B, D], [A, B, C, D, B], A];
type FlattenedTuple = Flatten<InputTuple>;
// Output: [A, B, C, D, A, B, D, A, B, C, D, B, A]

You can even achieve deep flattening by adding another layer of recursion as demonstrated below:

type FlattenDeep<T extends readonly any[], A extends readonly any[] = []> =
    T extends [infer F, ...infer R] ?
    FlattenDeep<R, F extends readonly any[] ? [...A, ...FlattenDeep<F>] : [...A, F]> :
    A

type InputDeepTuple = [A, B, [C, D], [A, B, D], [A, B, [[C], D], [B]], A];
type FlattenedDeepTuple = FlattenDeep<InputTuple>;
// Output: [A, B, C, D, A, B, D, A, B, C, D, B, A]

To test or play around with this code snippet, feel free to click on this interactive Playground link.


Answer for TypeScript 4.0:

In TypeScript 4.0, variadic tuple types are introduced which allow for simple concatenation of fixed tuples. Here's a basic implementation of Flatten<T>:

type ConcatX<T extends readonly (readonly any[])[]> = [
    ...T[0], ...T[1], ...T[2], ...T[3], ...T[4],
    ...T[5], ...T[6], ...T[7], ...T[8], ...T[9],
    ...T[10], ...T[11], ...T[12], ...T[13], ...T[14],
    ...T[15], ...T[16], ...T[17], ...T[18], ...T[19]
];
type Flatten<T extends readonly any[]> =
    ConcatX<[...{ [K in keyof T]: T[K] extends any[] ? T[K] : [T[K]] }, ...[][]]>

type InputTuple = [A, B, [C, D], [A, B, D], [A, B, C, D, B], A];
type FlattenedTuple = Flatten<InputTuple>;
// Output: [A, B, C, D, A, B, D, A, B, C, D, B, A]

You can experiment with this code here.


Pre-TypeScript 4.0 Update:

Working with complex types like nested arrays in TypeScript poses challenges due to limitations in the type system. While there are clever workarounds involving recursive conditional types, it's important to note that these approaches may not be future-proof and could impact compiler performance significantly. Officially, TypeScript does not support certain operations on tuples, such as recursive flattening.

The community, however, continues to explore solutions, with libraries like ts-toolbelt offering advanced tuple manipulation features. Proceed with caution when implementing non-standard tuples in your projects.

Answer №2

A proposal for variadic kinds in TypeScript has been put forward, which is currently set for the 4.0 release. This proposal aims to enhance jcalz@'s solution even further:

type Tuple = readonly any[]
type Tail<T extends Tuple> = T extends [any, ...infer U] ? U : []
type Concat<T extends Tuple, U extends Tuple> = [...T, ...U];
type Tuplize<T> = { [K in keyof T]: T[K] extends unknown[] ? T[K] : [T[K]] }

type Flatten<T extends Tuple> =
  Tuplize<T> extends infer U ?
    U extends Tuple ?
      { 0: [], 1: Concat<U[0], Flatten<Tail<U>>>}[U extends [] ? 0 : 1]
      : never
    : never;

It's important to note that this approach is based on an experimental proposal and lacks recursion control like jcalz@'s answer. Therefore, it should not be used in production until recursive conditional types are officially supported and the syntax for variadic kinds is finalized with the 4.0 release.

Nevertheless, it's exciting to speculate about the possibilities, isn't it? 😃


Playground Link

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