I have a union type defined as:
type A = "a" | "b" | "c";
Now, I want to create an interface like this:
interface B {
[index: A]: string
}
However, I need this interface to include all options from the union type, resulting in the following interface:
interface B {
a: string;
b: string;
c: string;
}
Is it possible to achieve this in TypeScript?
To accomplish this task, you can utilize a mapped type like so:
type B = {
[Key in A]: string
};
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