Retrieve only data that results in either a 1 or 0 when filtering

Currently, I am utilizing Angular2 with Typescript and making use of the filter method.

The functionality of the filter() method involves creating a new array that contains elements which successfully pass the test defined by the given function.

However, an issue arises when employing the logical operator "or" as it only yields either 1 or 0 result...

Here is how the code looks:

 public filter(url: string, id: number): Observable<any> {

return this.http.get<any>(url).pipe(map(param => {

  console.log('date' , param[1]['params'].filter(dato =>   new Date(dato.startdatevalidity).toLocaleDateString() === '15/3/2016'));


  let filter = param[1]['params'].filter(dato => dato.id === id)
    || param[1]['params'].filter(dato =>   new Date(dato.startdatevalidity).toLocaleDateString() === '15/3/2016')
    || param[1]['params'].filter(dato =>  new Date(dato.enddatevalidity).toLocaleDateString() === '15/4/2016');

  console.log('filter' , filter );

  return filter;
}
));
  }

Upon examining the console log output from (date), an Array containing 10 items is displayed - which is satisfactory.

Nevertheless, two dilemmas arise when dealing with the variable 'filter':

1. The first problem entails that when sending an id, the filter process solely incorporates that particular id resulting in just 1 outcome.

2. The second issue emerges when failing to send any id, leading to no results being generated.

In both these scenarios, the expected outcome should ideally be equivalent to the array length 10 displayed in the initial console log (date).

Answer №1

Your code doesn't seem to be logically sound.

When using array.filter(), it will always return an array which is considered truthy in JavaScript.

Therefore, the code you provided essentially boils down to

let filter = someArray || someOtherArray || someYetOtherArray;

As a result, this code will always return someArray because arrays are truthy values.

If your intention is to filter elements based on specific conditions, you should consider revising your code to something like

let filter = array.filter(element => someCheck(element) || someOtherCheck(element) || yetAnotherCheck(element))

This revised code snippet will only keep elements that satisfy at least one of the three specified conditions.

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