Looking for a solution to modify the characters within square brackets in a given string. For instance, I have a string that looks like "[A] [B] this is my [C] string". How can I update these bracketed characters by adding or removing brackets?
Looking for a solution to modify the characters within square brackets in a given string. For instance, I have a string that looks like "[A] [B] this is my [C] string". How can I update these bracketed characters by adding or removing brackets?
When it comes to handling this task, there are various approaches you can take depending on the requirements of your replacement function and the information it relies on. The following method focuses solely on replacing matched targets - A
, B
, C
- with predefined values based on the order of the brackets.
In this solution, I make use of both Array.reduce() and String.replace(), utilizing the regular expression detailed in the linked question:
To simplify the regex, you may choose to eliminate the parentheses used for capturing text, as it is not utilized in this scenario.
const replacements = [1, 2, 3];
const input = "[A] [B] this is my [C] string";
const output = replacements.reduce(
(string, replacement) => string.replace(/\[(.*?)\]/, replacement),
input
);
console.log(output);
The next approach assumes that the output depends on the content within the brackets rather than their order or appearance. This means that regardless of the sequence of placeholders in the string, [A]
would be replaced with 1
.
In this instance, I opt to employ String.replaceAll()
. The callback function receives three arguments, with descriptive names assigned: withBrackets
represents the full match like "[A]"
, innerText
signifies the text inside the brackets "A"
, and position
indicates the index where the match begins in the string.
const input = "[A] [B] this is my [C] string";
// If using TypeScript: const replacementFunction = (text: string): string => {
const replacementFunction = (text) => {
return text === "A" ? 1 : text === "B" ? 2 : 3
}
// No TypeScript required
const replaced = input.replaceAll(/\[(.*?)\]/g, (withBrackets, innerText, position) => {
// Implement logic for matching
return replacementFunction(innerText);
});
console.log(replaced)
When dealing with a string, follow these steps:
let givenString = "[X] [Y] this will be my [Z] text";
// identify the target substring and substitute it with another
const revisedString = givenString.replace("[Z]", "[W]");
console.log(revisedString);
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