As shown in the demo and indicated by the title
const { combineLatest, interval, of } = rxjs;
const { first, last, sample, take, withLatestFrom } = rxjs.operators;
const numbers = interval(1000);
const takeFourNumbers = numbers.pipe(take(4));
takeFourNumbers.subscribe(x => console.log('Next: ', x));
setTimeout(()=>{
console.log('how can we get the latest value which is 1?');
takeFourNumbers.pipe(first()).subscribe(v=>console.log(v,'actual get'))
},2500)
// Logs:
// Next: 0
// Next: 1
// how can we get the latest value which is 1?
// Next: 2
// 0 actual get
// Next: 3
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In my scenario, I specifically aim to retrieve the most recent value for a one-time task. How can this be achieved?
I have contemplated about the possibility of an operator such as takeLatest()
or latest()
, but haven't come across any.