Setting up the parameters for functions that encapsulate specified functions

Currently, I am in the process of creating a simple memoize function. This function is designed to take another function and perform some behind-the-scenes magic by caching its return value. The catch is that the types for the returned function from memoize should match exactly with the given function. However, I have encountered some errors that I am struggling to resolve. Interestingly, when I ignore these errors and proceed with using the function, it seems to work fine.

To illustrate my dilemma, I have created two functions. In my understanding, both types should be acceptable, but I am seeing more progress with the second implementation, although it still isn't functioning as expected.

You can test out the code on the TypeScript Playground. Just in case the link expires, here is a snapshot of the code alongside error screenshots:

function memoize1<F extends (...args: any[]) => Promise<any>>(func: F): F {
    return (...args) => func(...args)
}

function memoize2<F extends (...args: any[]) => Promise<any>>(func: F): (...args: Parameters<F>) => ReturnType<F> {
    return (...args) => func(...args)
}

const first = memoize1(() => {}) // Triggering complaints
const second = memoize1(async () => {}) // Works fine
const third = memoize2(() => {}) // Also triggering complaints
const fourth = memoize2(async () => {}) // Works like a charm

For reference, you can view the error images for the first example and the second example.

Answer №1

There is a compelling discussion on GitHub regarding the behavior mentioned in your query. Implementing an explicit cast to the desired type can resolve the compilation errors generated by the functions:

function memoize1<F extends (...args: any[]) => Promise<any>>(func: F): F {
    return ((...args) => func(...args)) as F
}

function memoize2<F extends (...args: any[]) => Promise<any>>(func: F): (...args: Parameters<F>) => ReturnType<F> {
    return (...args) => func(...args) as ReturnType<F>
}

The reason for the failure of your memoize1 function call is that the provided parameter function does not return a promise as specified by memoize1

F extends (...args: any[]) => Promise<any>

Therefore, calling memoize1(() => {}) with a function that returns an empty object and not a promise causes it to fail. By using the async keyword, the function's return type changes to a promise. This explains why memoize1(async () => {}) works.

For instance,

const first = memoize1(() => new Promise((resolve, reject)=> {})
passes a function that returns a promise and would compile successfully.

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