Streamline your Javascript code by utilizing multiple logical operators within a filter function

Looking for some help simplifying this code. Can anyone assist?

I need to make changes to this code because I made an error.

Correction needed:

    Updated test filter function:
    
    this._test = test?.filter(({ foo }: Foo) => {
        return foo.isTrue(foo.a)
            || foo.isTrue(foo.b)
            || foo.isTrue(foo.c)
            || foo.isSuperTrue(foo.d)
            || foo.isSuperTrue(foo.e)
            || foo.isSuperTrue(foo.f)
    }).slice(0, 3);

Answer №1

For more information on the Array.prototype.some method, you may refer to this link.

To modify the existing return statement, consider the following code snippet.

return [ foo.a, foo.b, foo.c, foo.d, foo.e, foo.f ].some(foo.isTrue)

Answer №2

To achieve this, ``some()`` can be utilized:

['x', 'y', 'z', 'm', 'n'].some(var => bar.checkIfTrue(bar[var]))

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