The expected TypeScript type was not properly inferred

In my scenario, I am looking to create a set of filters in the form of an object. I desire to have complete visibility into all available filters and enable auto-completion for them. However, I want the flexibility for any key to be used as long as it follows certain value types. I initially tried using generics and extends to achieve this, which worked partially. Yet, there were instances where the type unification based on extension did not behave as expected. Below is a simplified example illustrating what I tried:


    type Filters = { [key: string]: boolean | string[] }
    
    class Filter<T extends Filters> {
      constructor(public filter: T) {}
    }
    
    const filter = new Filter({ foo: false, bar: [] })
    
    console.log(filter.filter.foo) // Expected boolean instead of false
    
    for (const item of filter.filter.bar) {
      item.includes("x") // Error: Property 'includes' does not exist on type 'never'
    }
  

I anticipated that it would deduce `boolean` for `foo` and `string[]` for `bar`. It seems like the extension process does not merge the types as anticipated. Is there a way to accomplish this in TypeScript? Essentially, having full knowledge of the properties `foo` and `bar` within an instance of `Filter`, while internally treating them as generic types.

Answer №1

After receiving guidance from @jcalz in the comments section of my inquiry, I was able to find the solution I had been seeking. I followed his example closely when implementing it:

type Foo = { [key: string]: boolean | string[] }

type WidenFoo<T extends Foo> = { [K in keyof T]: T[K] extends boolean ? boolean : string[] };

class Bar<F extends Foo> {
    arg: WidenFoo<F>
    constructor(arg: F) {
        this.arg = arg as WidenFoo<F>;
    }
}
const bar = new Bar({ foo: false, bar: [] })

bar.arg.foo // boolean
bar.arg.bar // string[]

console.log(bar.arg.foo)
for (const n of bar.arg.bar) {    
    n.includes("x")
} 

In accordance with his advice and PR ms/TS#10676, literal types will be utilized whenever possible and will be narrowed down as much as feasible. Since TypeScript does not automatically widen literal types, we must manually broaden them using T extends Type ? Type : ... tricks. I tested it out and found that it works effectively for more intricate types like those in my scenario (which involve recursive types).

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