The generic type does not narrow correctly when using extends union

I'm working with the isResult function below:

export function isResult<
    R extends CustomResult<string, Record<string, any>[]>,
    K extends R[typeof _type]
>(result: R, type: K): result is Extract<R, { [_type]: K }> {
    return result[_type] === type;
}

const users = getUsers("abc");
if (isResult(users, "user")) {
    console.log(users.userProp);
} else {
    console.log(users.adminProp);
}

My objective is to:

  1. Enable auto suggestions for the second argument of isResult (in this case:
    "user" | "admin"
    ); and
  2. Ensure that isResult properly narrows down the types without errors;

However, I can only achieve one goal at a time. Auto complete works by using K extends R[typeof _type]. Proper narrowing only happens when using K extends string.

It appears that TypeScript treats K as the literal "user" under K extends string, but retains the entire union

"user" | "admin"
with K extends R[typeof _type].

The only method I found that satisfies both goals is using K extends R[typeof _type] along with

isResult(users, "user" as const)
.

I have two inquiries:

  1. Why does it work without as const when using K extends string?
  2. How can I eliminate the need for as const while retaining the auto suggestion for the second argument of isResult?

Complete Code: https://codepen.io/web-dev-sam/pen/gOJepNa

Answer №1

The solution for question 2 involves utilizing the following code snippet (refer to line 3):

export function isResult<
    R extends CustomResult<string, Record<string, any>[]>,
    const K extends R[typeof _type]
>(result: R, type: K): result is Extract<R, { [_type]: K }> {
    return result[_type] === type;
}

This effectively integrates the as const functionality into the type guard function.

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