The incorrect argument is being used to infer the generic type

I have implemented the NoInfer feature from the library called ts-toolbelt.

However, it seems that the example provided below does not reflect its intended effect.

In this scenario, the generic type is deduced from the util function as soon as it is introduced.

Observations include:

  • For demo1, no function argument is utilized resulting in a type of: { foo: string }
  • For demo2, a function argument _ is introduced leading to the type being inferred as unknown

Is there a method to enforce that the generic type is exclusively inferred from the return value so that demo2 shares the same type as demo1?

type NoInfer<T> = [T][T extends any ? 0 : never];

function factory<T>(generator: (util: (u: NoInfer<T>) => void) => T): T {
    return {} as any;
}

const demo1 = factory(() => {
    return {
        "foo": "bar"
    }
})

const demo2 = factory((_) => {
    return {
        "foo": "bar"
    }
})

// works
demo1.foo = "baz";
// ERROR! demo2 is unknown
demo2.foo = "baz";

Typescript Playground

Answer №1

Experiment

const example = generate<{bar: number}>((_) => { /* ... */ }

Make sure to specify the generic type when invoking the function.

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