The property 'options' is not found in the type of union type

In my development project, I have defined a couple of interface types and a union type:

export interface FieldOptions {
  value: string | number;
  viewValue: string;
}

export interface BaseField {
  id: string;
  derived?: boolean;
  required?: boolean;
}

export interface NumberField extends BaseField {
  type: 'number';
  decimals: number;
}
export interface SelectField extends BaseField {
  type: 'select' | 'select-multi';
  options: FieldOptions[];
  source?: string;
}

export type Field = NumberField | SelectField;

I've come across an issue with the usage of the union type Field. It means that a field can be either a Number or a Select.

To handle this situation, I've implemented a function in my Angular Component:

getField( key: string ): Field {
  return this.fields.filter( el => el.id === key )[ 0 ];
}

getFieldVersion2( key: string ): any {
  const field = this.fields.filter( el => el.id === key )[ 0 ];
  if ( (field as SelectField).options ) {
    return field as SelectField;
  } else {
    return field as Field;
  }
}

When using only the function getField in my template to retrieve a Field object, specifically a Select with an Options array of view/viewValues, I encounter a TypeScript error:

Property 'options' does not exist on type 'Field'.
   Property 'options' does not exist on type 'NumberField'.

My understanding is that Field is a union type of either Number or Select, where one has an options property and the other doesn't.

To address this issue, I introduced getFieldVersion2 in hopes of resolving it. However, unless I specify the result type as any, it will result in a build error.

The specific section of the template causing the compile error due to the use of options:

<mat-form-field  class="input">
  <mat-select formControlName="state">
    <mat-option *ngFor="let option of getField( 'state' ).options" [value]="option.value">
       {{option.viewValue}}
    </mat-option>
  </mat-select>
</mat-form-field>

In light of this situation, what could be a better approach to handling this scenario?

Answer №1

You have created an interface without the "options" property, and then assigned your "Field" type to it (or possibly another interface with the "options" property).

Now, you are trying to access the "options" property, which may or may not be present. This is causing a TypeScript error during compilation.

Changing the return type to "any" resolves the issue because the compiler won't attempt to infer the object's type being returned (thus assuming that "options" is a valid property and no error should occur).

If you plan to use the "options" property with the "Field" type, ensure its existence before compiling your TypeScript script.

Consider updating your methods to "getSelectField" and "getNumberField" as a potential solution...although there are other approaches to handling this situation.

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