The `Required<Partial<Inner>>` does not inherit from `Inner`

I stumbled upon a code snippet that looks like this:

type Inner = {
  a: string
}
type Foo<I extends Inner> = { f: I }
interface Bar<I extends Inner> {
  b: I
}
type O<I extends Partial<Inner>> = Foo<Required<I>> & Bar<Required<I>

Enjoy the Playground here

Unfortunately, this piece of code fails to compile and throws an error:

Type 'Required<I>' does not satisfy the constraint 'Inner'.
  Types of property 'a' are incompatible.
    Type 'I["a"]' is not assignable to type 'string'.
      Type 'string | undefined' is not assignable to type 'string'.
        Type 'undefined' is not assignable to type 'string'.ts(2344)

The goal was for

Required<Partial<Inner>>
to extend Inner.

Answer №1

The challenge arises from the fact that when I extends Partial<Inner>, it implies that I can be a subtype of Partial<Inner>. This means there are subtypes of Partial<Inner> that, even after being passed through Required, do not align with the I extends Inner constraint on Foo. An example of such a type is:

type Incompatible = Partial<Inner> & {a: undefined};

This is considered a valid subtype of Partial<Inner> because the definition of Partial<Inner> is {a?: string | undefined}. However, applying Required<Incompatible> does not transform it back into something that extends Inner; instead, it merely results in {a: undefined}. Trying to use this with Foo like so will fail for similar reasons as your mapped type fails:

type Q = Foo<Required<Incompatible>>;

Playground link

To resolve this issue in a type-safe manner will depend heavily on your specific scenario. One might be tempted to utilize:

type RequiredInner<T extends Partial<Inner>> = {
    [Key in keyof T]: T[Key] extends undefined ? Key extends keyof Inner ? Inner[Key] : never : T[Key];
};

...and then employ

Foo<RequiredInner<I>>
. While it may work, but it assumes something significant that might not hold true: There could exist a runtime value of {a: undefined} where you have that Partial<Inner>. This assumption lacks type safety. Therefore, we cannot provide a universal solution for addressing this in your actual code. Nevertheless, comprehending the problem should assist you in finding a resolution.

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