The specified property 'toString' is not found in the Typescript type

This particular situation was a bit perplexing for me. When I use the search function, I am seeking substring matches of the search keywords. Therefore, before comparing any object, I convert all properties to strings and check for substrings.

Based on my understanding, everything in JavaScript has a .toString method. Even when there is ambiguity in types, calling the method should not pose an issue.

For further clarity, here is the code snippet:

const results = rows.filter((row) =>
  fields.some((field) =>
    row[field].toString().toLowerCase().includes(search)
  )
);

The variable rows is of type ListFields[L], where L is a generic that extends keyof ListFields. The variable fields is an array of type keyof ListFields[L], so accessing non-existent properties should not be a concern.

Below is the definition for ListFields:

type ListFields = {
  Users: MetaData &
    LocationData & {
      wuNumber: string;
      dispName: string;
      firstName: string;
      lastName: string;
    };
  // ... Other similar list definition
}

// Definitions for MetaData and LocationData if needed:
type MetaData = {
  Title: string | null;
  FileSystemObjectType: number;
  Id: number;
  ServerRedirectedEmbedUri: null | string;
  ServerRedirectedEmbedUrl: string;
  ID: number;
  ContentTypeId: string;
  Modified: string;
  Created: string;
  AuthorId: number;
  EditorId: number;
  OData__UIVersionString: string;
  Attachments: boolean;
  GUID: string;
  ComplianceAssetId: null | number;
};

type LocationData = {
  Address: string;
  CountryOrRegion: string;
  State: string;
  City: string;
  PostalCode: string;
  Street: string;
  GeoLoc: string;
};

Answer №1

Even though data types like string, boolean, and number have a toString function, the null data type does not have one. To handle this, you can opt to either use JSON.stringify or remove properties that contain null as an option.

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