The transition from an unknown type to a known type occurs through type inference when a method is

In my current project, I have a class with a single generic parameter T. The challenge arises when this class is sometimes constructed with a known value for T, and other times without a value, leaving T in an unknown state. It becomes cumbersome to always specify the type explicitly, especially when inference could potentially handle it.

This issue can be simplified to a specific problem I'm encountering with another class that requires T to be defined rather than remain unknown, even if no initial value is provided as it may be assigned later on.

class Foo<T> {
    value: T;

    constructor(value?: T) {
        if (value != null && value != undefined) {
            this.value = value;
        }
    }

    public set(value: T) {
        this.value = value;
    }
}

const fn1 = (): Foo<number> => {
    const foo = new Foo(0); //foo is Foo<number>
    foo.set(1);

    return foo; //No error
}

const fn2 = (): Foo<number> => {
    const foo = new Foo(); //foo is Foo<unknown>
    foo.set(1);
    
    // Although 'unknown' accepts 'number' values, 
    // I aim to re-evaluate foo as Foo<number>.
    
    return foo; //Error
}

const fn3 = (): Foo<number> => new Foo(); //No error, inferred as Foo<number>

I find myself wondering if there's a way to update the generic type from unknown to a specific type in such scenarios?

Alternatively, is there a mechanism to prevent the type from ever becoming unknown? Perhaps enforcing the specification of a type when calling new Foo()? Additionally, while using Foo<any> offers some flexibility, is there a technique to make any the default type?

I acknowledge that one simple solution would involve explicitly stating new Foo<number>(), but ideally, TypeScript should be able to deduce types without manual intervention, thus minimizing unnecessary efforts.

Answer №1

Would it be possible to set any as the default?

Absolutely, you can achieve this by using a default type for your generic:

class Foo<T = any> {}

Playground Link

Answer №2

Is there a way to make the generic type re-evaluate and not remain as unknown?

Regrettably, TypeScript does not re-evaluate the generic type. According to the documentation, the inference of a generic class instance type occurs only at instantiation:

When a generic class is instantiated with new, its type parameters are inferred in a similar manner to a function call

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