Transform information into a different format and showcase it in a table

Question

Transform information into a different format and showcase it in a table

Hey there, currently I am working with Typescript on Angular 9. I have a dataset that is structured like the example below and I need to present it in a mat-table.

Is there a way to transform it as follows?

0: CustomPoDTO {id: "1", equipmentOrdered: "Monitor, Keyboard", quantity: 2}
1: CustomPoDTO {id: "2", equipmentOrdered: "Keyboard, Monitor, Mouse", quantity: 6}
2: CustomPoDTO {id: "3", equipmentOrdered: "Mouse", quantity: 2}

to look like this?

0: CustomPoDTO {id: "1", equipmentOrdered: "Monitor and 1 more", quantity: 2}
1: CustomPoDTO {id: "2", equipmentOrdered: "Keyboard and 2 more", quantity: 6}
2: CustomPoDTO {id: "3", equipmentOrdered: "Mouse", quantity: 2}

angular typescript mat-table

Answer 1

Answer №1

To effectively showcase information based on the provided data, consider utilizing the equipmentOrdered column and formatting it with a Pipe instead of directly altering the data itself.

<ng-container matColumnDef="equipmentOrdered">
  <th mat-header-cell *matHeaderCellDef>Ordered Equipment</th>
  <td mat-cell *matCellDef="let item">{{ item.equipmentOrdered | displayMore }} </td>
</ng-container>

@Pipe({name: 'displayMore '})
export class DisplayMorePipe implements PipeTransform {
  transform(value: string): string {
    const [firstItem, ...others] = value.split(',');
    return others.length > 0 ? `${firstItem} and ${others.length} more` : firstItem;
  }
}

Answer 2

To effectively showcase information based on the provided data, consider utilizing the equipmentOrdered column and formatting it with a Pipe instead of directly altering the data itself.

<ng-container matColumnDef="equipmentOrdered">
  <th mat-header-cell *matHeaderCellDef>Ordered Equipment</th>
  <td mat-cell *matCellDef="let item">{{ item.equipmentOrdered | displayMore }} </td>
</ng-container>

@Pipe({name: 'displayMore '})
export class DisplayMorePipe implements PipeTransform {
  transform(value: string): string {
    const [firstItem, ...others] = value.split(',');
    return others.length > 0 ? `${firstItem} and ${others.length} more` : firstItem;
  }
}

Answer 3

Answer №2

Simply tally the total number of equipment items ordered

const equipmentOrders = [{id: "1", equipmentOrdered: "Monitor, Keyboard", quantity: 2},
            {id: "2", equipmentOrdered: "Keyboard, Monitor, Mouse", quantity: 6},
            {id: "3", equipmentOrdered: "Mouse", quantity: 2}]

equipmentOrders.forEach((order) => {
   splitEquipment = order['equipmentOrdered'].split(',')
   if (splitEquipment.length > 1) {
     order['equipmentOrdered'] = `${splitEquipment[0].trim()} and ${(splitEquipment.length - 1)} more`
   }
   
})

console.log(equipmentOrders);

Answer 4

Simply tally the total number of equipment items ordered

const equipmentOrders = [{id: "1", equipmentOrdered: "Monitor, Keyboard", quantity: 2},
            {id: "2", equipmentOrdered: "Keyboard, Monitor, Mouse", quantity: 6},
            {id: "3", equipmentOrdered: "Mouse", quantity: 2}]

equipmentOrders.forEach((order) => {
   splitEquipment = order['equipmentOrdered'].split(',')
   if (splitEquipment.length > 1) {
     order['equipmentOrdered'] = `${splitEquipment[0].trim()} and ${(splitEquipment.length - 1)} more`
   }
   
})

console.log(equipmentOrders);

Answer 5

Answer №3

To achieve the expected result, follow these instructions:

  Iterate through each element in the array using the forEach method:
   array.forEach(element => {
   Extract the elements in the 'equipmentOrdered' property by splitting the string at the comma:
   const tempString = element.equipmentOrdered.split(',');

   Save the first element from the split string:
   let stringFormation = tempString[0];

   Check if there are more than one element in the split array:
   if(tempString.length > 1) {
   If there are more elements, update the 'stringFormation' variable to include ' and (number of elements - 1) more':
   stringFormation = stringFormation + ' and ' + String(tempString.length-1) + ' more';
  }
  Update the 'equipmentOrdered' property of the element with the modified string:
  element.equipmentOrdered = stringFormation;
});

Answer 6

To achieve the expected result, follow these instructions:

  Iterate through each element in the array using the forEach method:
   array.forEach(element => {
   Extract the elements in the 'equipmentOrdered' property by splitting the string at the comma:
   const tempString = element.equipmentOrdered.split(',');

   Save the first element from the split string:
   let stringFormation = tempString[0];

   Check if there are more than one element in the split array:
   if(tempString.length > 1) {
   If there are more elements, update the 'stringFormation' variable to include ' and (number of elements - 1) more':
   stringFormation = stringFormation + ' and ' + String(tempString.length-1) + ' more';
  }
  Update the 'equipmentOrdered' property of the element with the modified string:
  element.equipmentOrdered = stringFormation;
});

Answer 7

Answer №4

const purchases = [
    {id: "1", itemsPurchased: "T-shirt, Jeans", quantity: 3},
    {id: "2", itemsPurchased: "Jeans, Shoes, Socks", quantity: 2},
    {id: "3", itemsPurchased: "Socks", quantity: 1}
];

purchases.forEach(purchase => {
    if(purchase.itemsPurchased.includes(',')){
        quantity = purchase.quantity -1;
        purchase.itemsPurchased = purchase.itemsPurchased.split(',').shift() + ' and ' + quantity+ ' more';
    }
});

console.log(purchases)

Answer 8

const purchases = [
    {id: "1", itemsPurchased: "T-shirt, Jeans", quantity: 3},
    {id: "2", itemsPurchased: "Jeans, Shoes, Socks", quantity: 2},
    {id: "3", itemsPurchased: "Socks", quantity: 1}
];

purchases.forEach(purchase => {
    if(purchase.itemsPurchased.includes(',')){
        quantity = purchase.quantity -1;
        purchase.itemsPurchased = purchase.itemsPurchased.split(',').shift() + ' and ' + quantity+ ' more';
    }
});

console.log(purchases)

Transform information into a different format and showcase it in a table

Answer №1

Answer №2

Answer №3

Answer №4

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