Troubleshooting a React Native application: Solutions for resolving the error - navigation.setOptions is not a recognized function

Question

Troubleshooting a React Native application: Solutions for resolving the error - navigation.setOptions is not a recognized function

Below is the test scenario:


describe('<HomeScreen />', () => {
  it('Should render correctly', () => {

// const setOptions = jest.fn(); // 1
// const setOptions = (navigation: any, route: any) => { } // 2
//   const setOptions = (props: HomeProps) => { } // 3
//  const setOptions = (options: Partial<NativeStackNavigationOptions>) => void // 4

    render(
      <Provider store={store}>
        <PersistGate loading={null} persistor={persistor}>
          <HomeScreen navigation={{ setOptions: setOptions }} route={undefined} />
        </PersistGate>
      </Provider>,
    );
  });
});

I have attempted the solutions provided here and here, but unfortunately, none of them seem to work in my case.

The issue seems to be related to the usage of TypeScript and React Navigation v6, as indicated by the errors I am encountering:

const setOptions = jest.fn(); results in:

Type '{ setOptions: jest.Mock<any, any>; }' is not assignable to type 'NativeStackNavigationProp<RootStackParamList, "Home">'.

The component's type is

NativeStackNavigationProp<RootStackParamList, "Home">

.

This type is defined as:

export type HomeProps = NativeStackScreenProps<RootStackParamList, 'Home'>;

Which is later imported as HomeProps

const setOptions = (navigation: any, route: any) => { }

This leads to the error:

Type '(navigation: any, route: any) => void' is not assignable to type '(options: Partial<NativeStackNavigationOptions>) => void'.

const setOptions = (props: HomeProps) => { }

This gives the error:

Type '(props: HomeProps) => void' is not assignable to type '(options: Partial<NativeStackNavigationOptions>) => void'.

const setOptions = (options: Partial<NativeStackNavigationOptions>) => void

(suggested by @captain-yossarian)

The error received is:

Type '{ setOptions: (options: Partial<NativeStackNavigationOptions>) => any; }' is not assignable to type 'NativeStackNavigationProp<RootStackParamList, "Home">'.

How can I address this issue?

typescript react-native react-testing-library react-native-testing-library react-navigation-v6

Answer 1

Answer №1

Take a look at this illustrative scenario:

import React, { FC, useEffect } from "react";
import { View } from "react-native";
import "react-native";
import { render } from "@testing-library/react-native";
import { NativeStackScreenProps, NativeStackNavigationProp } from "@react-navigation/native-stack";

type RootStackParamList = {
  App: undefined;
};

export type AppProps = NativeStackScreenProps<RootStackParamList, "App">;

const App: FC<AppProps> = ({ navigation }) => {
  useEffect(() => {
    navigation.setOptions({
      headerRight: () => <View>hello</View>,
      gestureEnabled: false
    });
  });

  return <View>Hello</View>;
};

export default App;


const setOptions = (options: NativeStackNavigationProp<RootStackParamList, "App">) =>
  void (
    // 4

    render(
      <App navigation={options} route={{ key: 'hello', name: "App", }} />
    )
  );

Interactive Example

The utilization of

NativeStackNavigationProp<RootStackParamList, "App">

type is crucial for the variable options

Answer 2

Take a look at this illustrative scenario:

import React, { FC, useEffect } from "react";
import { View } from "react-native";
import "react-native";
import { render } from "@testing-library/react-native";
import { NativeStackScreenProps, NativeStackNavigationProp } from "@react-navigation/native-stack";

type RootStackParamList = {
  App: undefined;
};

export type AppProps = NativeStackScreenProps<RootStackParamList, "App">;

const App: FC<AppProps> = ({ navigation }) => {
  useEffect(() => {
    navigation.setOptions({
      headerRight: () => <View>hello</View>,
      gestureEnabled: false
    });
  });

  return <View>Hello</View>;
};

export default App;


const setOptions = (options: NativeStackNavigationProp<RootStackParamList, "App">) =>
  void (
    // 4

    render(
      <App navigation={options} route={{ key: 'hello', name: "App", }} />
    )
  );

Interactive Example

The utilization of

NativeStackNavigationProp<RootStackParamList, "App">

type is crucial for the variable options

Answer 3

Answer №2

Another option is:

Instead of using HomeProps, I can switch to utilizing HomeNavigationProp within the navigation types:

export type HomeProps = NativeStackScreenProps<RootStackParamList, 'Home'>;

export type HomeNavigationProp = HomeProps['navigation'];


describe('<HomeScreen />', () => {
  it('Displays correctly', () => {
    const navigation: HomeNavigationProp = null;

const { getByText } = render(
      <Provider store={store}>
        <PersistGate loading={null} persistor={persistor}>
          <HomeScreen navigation={navigation} route={undefined} />
        </PersistGate>
      </Provider>,

getByText("hello");
    )
  });

Answer 4

Another option is:

Instead of using HomeProps, I can switch to utilizing HomeNavigationProp within the navigation types:

export type HomeProps = NativeStackScreenProps<RootStackParamList, 'Home'>;

export type HomeNavigationProp = HomeProps['navigation'];


describe('<HomeScreen />', () => {
  it('Displays correctly', () => {
    const navigation: HomeNavigationProp = null;

const { getByText } = render(
      <Provider store={store}>
        <PersistGate loading={null} persistor={persistor}>
          <HomeScreen navigation={navigation} route={undefined} />
        </PersistGate>
      </Provider>,

getByText("hello");
    )
  });

Troubleshooting a React Native application: Solutions for resolving the error - navigation.setOptions is not a recognized function

Answer №1

Answer №2

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