Typescript, bypassing the parameter's data type

I came across the following code snippet:

const myObject = new Object();
myObject['test'] = 'hello';

calc(myObject['test']);

function calc(x: number) {
  console.log(x * 10);
}

This example is quite straightforward.

I expected TypeScript to raise a compile-time error indicating that it cannot determine the concrete type while calc expects a number.

To my surprise, TypeScript remained silent and the console displayed NaN.

The issue caught my attention when working with Angular 4 and routing data.

const routes: Routes = [
    {
        path: '**',
        data: [{error: new ApplicationError('http-status-404', '', HttpErrorStatus.NotFound)}],
        component: ApplicationErrorComponent,
        resolve: {
            error: ApplicationErrorResolve
        }
    }
];

@Injectable()
export class ApplicationErrorResolve implements Resolve<ApplicationError> {

   constructor(private applicationErrorHandler: ApplicationErrorHandler) { }

   resolve(route: ActivatedRouteSnapshot, state: RouterStateSnapshot): ApplicationError {

        if (route.data != null && route.data[0]['error'] instanceof ApplicationError) {
            this.applicationErrorHandler.addError(route.data[0]);

            return route.data[0];
        }

        return null;
    }
}

// signature of applicationErrorHandler.addError
addError(error: ApplicationError, navigateToErrorPage: boolean = true) {

}

In the provided code, ApplicationError was expected to be in route.data[0].error but not in route.data[0]. However, TypeScript did not throw any errors, leading to incorrect object types during runtime.

Is there a way to address this issue without manual type checking through instanceof or similar methods? Perhaps some type guard or stricter TypeScript flag like --strictNullCheck?

Coming from a C# background, this behavior was surprising and concerning.

EDIT

Thanks to Saravana, the simple example initially provided works fine. But when arrays are involved, issues resurface even with noImplictAny = true.

 const myArray = new Array<any>();
 myArray[0] = { name: 'test'};
 myArray[1] = { name: 1} ;

 // TypeScript doesn't complain 
 this.calc(myArray[0]);

 // TypeScript doesn't complain
 this.calc(myArray[0].ImActuallyNotPresent);

 function calc(x: number) {
     console.log(x * 10);
 }

I'm confused. Why does this happen? I understand that it relates to the use of any, but why does the definition of myArray override my method's signature? This inconsistency provides a false sense of security.

Is there a solution to this problem?

Answer №1

In order to catch these issues, you must either set "noImplicitAny": true in your tsconfig.json file or use the --noImplicitAny flag when compiling.

If you have enabled noImplicitAny, the type of myObject['test'] will be checked against calc. Without it, the type is considered as any, allowing it to be passed without any type checking.

Enabling "noImplicitAny": true results in an error like:

Element implicitly has an 'any' type because type 'Object' has no index signature.

For more information on TypeScript compiler options, visit: https://www.typescriptlang.org/docs/handbook/compiler-options.html


When you utilize

const myArray = new Array<any>();
, you are essentially stating that myArray can contain anything. The compiler only verifies that it is an array, not the contents within it. This explains why myArray[0].ImActuallyNotPresent doesn't trigger errors—it's due to the lack of specified content types.

To enforce type checking on array content, define the type for the array elements:

interface MyArrayContent {
  someString: string;
  someNumber: number
}

const myArray = new Array<MyArrayContent>();
myArray[0] = { someString: 'test', someNumber: 1 };
myArray[1] = { someString: "test2", someNumber: 2};

calc(myArray[0]); // Error
calc(myArray[0].ImActuallyNotPresent); // Error
calc(myArray[0].someString); // Error
calc(myArray[0].someNumber); // No error

function calc(x: number) {
  console.log(x * 10);
}

any in TypeScript allows bypassing all type checks and entering full JS-mode, disregarding compile time verifications. It behaves differently from statically-typed languages like C#. Consider any as a way to disable type checks universally for a variable's usage.

More on any: https://www.typescriptlang.org/docs/handbook/basic-types.html#any

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