Typescript: Declaring object properties with interfaces

Looking for a solution to create the childTitle property in fooDetail interface by combining two properties from fooParent interface.

export interface fooParent {
   appId: string,
   appName: string
}

export interface fooDetail {
  childTitle: fooParent.appId + '-' + fooParent.appName
}

Any ideas on how to implement this?

childTitle: fooParent.appId + '-' + fooParent.appName

Answer №1

You have the option to utilize template literal strings:

export interface parentFoo {
    id: string,
    name: string
}

export interface detailFoo {
    title: `${parentFoo['id']} - ${parentFoo['name']}`
}

If you want to explore inference, you can refer to this illustration:

export interface parentFoo {
    id: string,
    name: string
}

export interface detailFoo {
    title: `${parentFoo['id']} - ${parentFoo['name']}`
}

const functionHandler = <
    Id extends string,
    Name extends string,
    Parent extends parentFoo & { id: Id, name: Name }
>(parent: Parent): `${Parent['id']} - ${Parent['name']}` =>
    `${parent.id} - ${parent.name}`

const outcome = functionHandler({ id: '#1', name: 'App' }) // "#1 - App"

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