Typescript: Retrieve an interface containing properties that are found in interface A, but not in interface B

I am currently developing a mapper that will facilitate the translation between a serialized entity state and a form state.

In the context of two given interfaces A and B, I am exploring ways to derive a third interface C that includes properties present in A but not in B. How can I achieve this?

interface A {
    name: string;
    age: number;
    id: string;
    version: number;
}

// Potentially defined as interface B extends Omit<A, "version" | "id"> {}
interface B {
    name: string;
    age: number;
}

interface PropertiesPresentInADeficientInB {
    // ???
}

// Here is an illustration of my mapper interface for this use case
interface IEntityFormStateMapper<
  E extends Entity<A>,
  FS extends B,
  OP extends PropertiesPresentInADeficientInB
> {
  toEntity: (formState: FS, omittedEntityProps: OP) => Result<Error, E>;
  toFormState: (entity?: E) => Result<Error, [FS, OP]>;
}

Answer №1

The solution you're looking for is quite straightforward: Omit<A, keyof B>.

If you plan to use it in various locations, feel free to assign it an alias such as

type PropertiesOfAButNotB = Omit<A, keyof B>
.

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