TypeScript struggles with resolving types in union types

Imagine you have a data structure that can either be an array of numbers or strings and you intend to iterate over this array. In TypeScript, there are various ways to handle this scenario that are all validated by the type checker.

[1, 2].map(e => console.log(e));
let arr: string[] | number[] = [1, 2];
arr.map(e => console.log(e));

However, when adding an explicit static type cast to describe the same type for arr, the compiler may throw an error:

(arr as string[] | number[]).map(e => console.log(e)); 
// Cannot invoke an expression whose type lacks a call signature. 
// Type '(<U>(callbackfn: (value: string, index: number, array: string[]) => U, thisArg?: any) => U[]) | (...' has no compatible call signatures.

Have you ever wondered why this error occurs, or could it potentially be a flaw in the compiler itself?

Answer №1

In the initial case, you can observe flow control analysis at work. When you assign a number array to a variable, the compiler determines that the actual type for arr is number[], allowing the map call to be valid. However, if you assign a string[] to the variable and the compiler cannot statically determine which code path will be taken, you will encounter an error similar to when using an explicit cast:

declare var decider : boolean
let arr: string[] | number[] = decider ? [1, 2] : ['a', 'b'];
arr.map(e => console.log(e)); // Will result in an error 

The reason why map cannot be called on the union of string[] | number[] is because the type of map becomes a union type of the two available signatures from string[] and number[]. These signatures are not identical, and they do not merge. Since a union of two signatures is not callable, an error occurs.

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