When looking at the code below:
type A = number | undefined
type B<C extends number> = C
let a: B<A>;
An error will be generated as follows:
Type 'A' does not satisfy the constraint 'number'. Type 'undefined' is not assignable to type 'number'.Can we assume that A will always be defined, like this:
let a: B<A!>
// or
let a: B<NonNullable<A>>
?
The purpose of the non-null assertion operator is to be utilized with JavaScript variables. Using it with TypeScript types does not really make sense.
It seems like the issue you are encountering stems from another source that needs to be addressed instead.
For a quick resolution, consider utilizing the Exclude utility type.
Complete solution:
type A = number | undefined
type B<C extends number> = C
const a: B<Exclude<A, undefined>> = 234;
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