Using type annotations and discriminated unions with string literals

Recently, I encountered an issue while trying to create objects that adhere to a specific type annotation (Cards). The challenge was with a property that needed to match a discriminated union of string literals (CardType). These string literals were identical to the ones on the original type annotation.

// ------------ SETTING UP ------------
interface AboutCard {
  type: 'About'
}

interface SplashCard {
  type: 'Splash'
}

export type Cards = AboutCard | SplashCard
export type CardType = 'About' | 'Splash'

const type = 'About' as CardType
// ------------ SETUP END ------------

const example1: Cards = {
  type
}

// ^
// Type 'CardType' is not assignable to type '"Splash"'.
// Type '"About"' is not assignable to type '"Splash"'.ts(2322)

const example2 = {
  type
} as Cards

// ^ all good, no error.

const example3 = {
  type: 'NOT_REAL_CARD'
} as Cards

// ^
// Types of property 'type' are incompatible.
// Type '"NOT_REAL_CARD"' cannot be assigned to type '"Splash"'.ts(2352)

This got me thinking, why did the first example fail while the last two examples executed as expected?

const example1: Cards = {
type
}

Even though example1 appears to meet the requirements of the Cards type, assigning any value other than explicitly stated string literals like About or Splash created issues. It seems to struggle when dealing with a discriminated union.

I apologize if my explanation isn't clear enough!

This discussion on why TypeScript converts string literal union types to strings during assignment may shed some light on the situation.

Answer №1

In cases where there are no additional properties involved, the difference between { type: 'About' | 'Splash' } and

{ type: 'About' } | { type: 'Splash' }
is significant. When your variable type encompasses all possible discriminants in a union, attempting to assign an object with key type that represents a union property where a discriminated union is expected will lead to issues.

The reason why the last two examples function as intended is due to the flexibility provided by a type assertion. By using this approach, you essentially inform the compiler to ignore any potential type errors it may identify.

To grasp the reasons behind the incompatibility of these types, consider the following example:

interface AboutCard {
    type: 'About'
    aboutMessage: string
}

interface SplashCard {
    type: 'Splash'
    splashMessage: string
}

export type Cards = AboutCard | SplashCard
export type CardType = Cards['type'] // eliminating the repetition of string literal types

const type = 'About' as CardType

// What properties should be required for `example1` ? 
// in this scenario, since it combines both types simultaneously, ideally all properties within the union should be mandated
const example1: Cards = {
    type,
    splashMessage: ""
}

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