Using Typescript: Utilizing only specific fields of an object while preserving the original object

I have a straightforward function that works with an array of objects. The function specifically targets the status field and disregards all other fields within the objects.

export const filterActiveAccounts = ({
  accounts,
}: {
  accounts: Array<{ status: string; }>;
}) =>
  accounts.filter(({ status }) => status === 'active')

My aim is for the function to return the same type of object as the one passed in. This means I should be able to use it like this:

type FoobarAccount {
  status: string;

  baz: string;
  lorem: string;
}

const foobarAccounts = [
  { status: "active", baz: "xxx", lorem: "xxx" },
  { status: "pending", baz: "xxx", lorem: "xxx" },
]

const active_accounts: Array<FoobarAccount> = filterActiveAccounts({ accounts: foobarAccounts })

However, the current definition of filterActiveAccounts results in a return type of Array<{ status: string; }>, which triggers a Typescript error in this scenario.

My intuition tells me that I may need to utilize generics, but I'm uncertain about how to implement them.

Answer №1

To capture the actual type passed in, simply include a type parameter within the function. This will automatically infer the return type to be the same as the type that was passed in:

export const filterActiveAccounts = <T extends { status: string; }>({
  accounts,
}: {
  accounts: Array<T>;
}) =>
  accounts.filter(({ status }) => status === 'active')

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