Utilizing generic functions as arguments in other functions

Imagine if I were to create a type called CoolType in this manner:

type CoolType<T> = {message: string, result: T} 

Next, let's define a type called CoolFunction which represents a function that returns CoolType:

type CoolFunction = <T>() => CoolType<T>

CoolFunction is the type expected as a parameter by another function:

function superCoolFunction(coolFunction: CoolFunction) {
    return coolFunction()
}

After all these definitions, We try running some code like this:

const res = superCoolFunction(<string>() => {
    return {message: 'I am the message', result: 'I am the result'}
})

However, when reaching <string>() => {, an error is thrown by the compiler stating that

'string' is declared but its value is never read.ts(6133) Argument of type '() => { message: string; result: string; }' is not assignable to parameter of type 'CoolFunction'. Call signature return types '{ message: string; result: string; }' and 'CoolType' are incompatible. The types of 'result' are incompatible between these types. Type 'string' is not assignable to type 'T'. 'string' is assignable to the constraint of type 'T', but 'T' could be instantiated with a different subtype of constraint '{}'.ts(2345)

Do you have any thoughts on what might be causing this issue? Here's a stackblitz link for reference.

Answer №1

Your placement of generics seems to be causing issues. Consider revising it as follows:

type AwesomeFunction<T> = () => AwesomeType<T>;

In this case, AwesomeFunction should also have a generic type parameter. This way, your higher-order function can pass on the generic type:

function superAwesomeFunction<T>(awesomeFunction: AwesomeFunction<T>): AwesomeType<T> {
    return awesomeFunction();
}

This setup allows the compiler to infer the specific type automatically:

superAwesomeFunction(() => ({ message: 'hello', result: 456 }));
// function superAwesomeFunction<number>(awesomeFunction: AwesomeFunction<number>): AwesomeType<number>

You can also explicitly provide the type like this:

superAwesomeFunction<string>(() => ({ message: 'greetings', result: 'world' }));

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