Utilizing TypeScript for various return types with the same parameters

Exploring TypeScript Signatures

In an effort to embrace TypeScript fully, I am implementing strongly typed signatures in my Components and Services, including custom validation functions for angular2 forms.

I have discovered that while function overloading is possible, each signature must have different parameters because tsc compiles them into separate functions:

function pickCard(x: {suit: string; card: number; }[]): number;
function pickCard(x: number): {suit: string; card: number; };
function pickCard(x): any { /*common logic*/ };

Furthermore, I found that returning a single type like a Promise can also be versatile by supporting multiple sub-types:

private active(): Promise<void|null> { ... }

However, the challenge arises when dealing with angular2 custom form validators where a single parameter of type FormControl can return either an Object with errors or null to signify no errors.

The traditional approaches do not work as expected:

private lowercaseValidator(c: FormControl): null;
private lowercaseValidator(c: FormControl): Object {
    return /[a-z]/g.test(c.value) ? null : { lowercase: this.validationMessages.lowercase };
}

Consequently, using any seems like a fallback option that undermines the benefits of having type signatures.

Future Perspective on ES6

This dilemma extends beyond just angular2 form validators to more general scenarios, especially considering upcoming ES6 features like rest parameters (function (a, b, ...others) {}). While it may seem advisable to avoid functions returning multiple types, it remains a common practice given JavaScript's dynamic nature.

References

Answer №1

Alright, here's a correct approach if you aim for accurate types:

type SpecificType = { lowercase: TypeOfTheProperty };
// I'm unable to determine the type of this.validationMessages.lowercase accurately without more context on the entire class. My assumption is that it might be an Array<string> or string, but since I'm not well-versed in Angular, it's just speculation.

private lowercaseValidation(c: FormControl): SpecificType | null {
    return /[a-z]/g.test(c.value) ? null : { lowercase: this.validationMessages.lowercase };
}

A More Universal Example

type SpecificType = { lowercase: Array<string> };

class B {
      private items: Array<string>;

      constructor() {
            this.items = Array<string>();
            this.items.push("carrot");
            this.items.push("dog");
      }

      public validateInputs(bool: boolean): SpecificType | null {
            return bool ? null : { lowercase: this.items };
      }
}

let b = new B();
let specificObj: SpecificType | null = b.validateInputs(false);
// If strictNullChecks are enabled, both SpecificType and null must be specified
// Otherwise, using just SpecificType would suffice

Answer №2

In addition to what Erik mentioned, in the final line of his second example, instead of repeating the type declaration, you have the option to utilize the "as" keyword.

let customObj = a.testMethod(false) as CustomType;

Essentially, if you encounter a function with multiple return types, you can specify which type should be assigned to a variable using the "as" keyword.

type Person = { name: string; age: number | string };

const employees: Person[] = [
  { name: "John", age: 42},
  { name: "April", age: "N/A" }
];

const canTakeAlcohol = employees.filter(emp => {
  (emp.age as number) > 21;
});

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